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Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields It only takes a minute to sign upD Ñ b Q c _ á 0° í 8 @ * W K S _/ x M 84* o _ c W0° b ^4* o @ 6 ~ r M 4* o ¡>& ö =/ !m>' Ñ !E h y M X ö c ³ Û Æ d Q ¤, ¥ W O d } M u j z, y Q v @ p O q O d V h b q M u j v u ^ s n q O d V o V y, v u ^ s ^ Z s b q M Z ^ s z Ù þ r @ d } M u j z Ü ¢ ñ Ç ¹ Á Æ t Q # S d V ¢ ñ Æ ë ¾ µ å ñ °H)RU6KH W Ó ² T ± v
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ƒ~ƒ‰ƒRƒXƒ^ —\–ñ "d˜b ƒRƒc-Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorC u y z PO y k \ } r S d y D è ã Á v ô b d O ± ñ Ï Æ u ³ ¢ ¸ ° y D E æ @ ± z Ï Á v E æ @ s E æ P z W Ø n q U Ï Á u y = r X d } E æ @ y v E æ P X PO y ü b Ï W ^ s W r X d } K ¨ r z ç v ó
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Its not a good idea to use subtraction, for by default that relation is not symmetric However you are correct But I would suggest the following $(a,b)R(c,d) \iff ad =bc \equiv (a,b)R(a,b) \iff ab =ab$ therefore R is trivially reflexive $$(c,d)R(a,b) \iff cb=da $$*and so ad=bc, which means (a,b)R(c,d)*Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorPREVIEW ACTIVITY \(\PageIndex{1}\) Sets Associated with a Relation As was indicated in Section 72, an equivalence relation on a set \(A\) is a relation with a certain combination of properties (reflexive, symmetric, and transitive) that allow us to sort the elements of the set into certain classes
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